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24x^2+48x-72=0
a = 24; b = 48; c = -72;
Δ = b2-4ac
Δ = 482-4·24·(-72)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9216}=96$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-96}{2*24}=\frac{-144}{48} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+96}{2*24}=\frac{48}{48} =1 $
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