24x2+110x+100=0

Solution for 24x2+110x+100=0 equation:

24x^2+110x+100=0

a = 24; b = 110; c = +100;
Δ = b2-4ac
Δ = 1102-4·24·100
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-50}{2*24}=\frac{-160}{48}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+50}{2*24}=\frac{-60}{48}
=-1+1/4
$