24x-12(x-2)=6(x+3)+6

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Solution for 24x-12(x-2)=6(x+3)+6 equation: 



24x-12(x-2)=6(x+3)+6

We move all terms to the left:

24x-12(x-2)-(6(x+3)+6)=0

We multiply parentheses

24x-12x-(6(x+3)+6)+24=0



We calculate terms in parentheses: -(6(x+3)+6), so:

6(x+3)+6

We multiply parentheses

6x+18+6

We add all the numbers together, and all the variables

6x+24

Back to the equation:

-(6x+24)



We add all the numbers together, and all the variables

12x-(6x+24)+24=0

We get rid of parentheses

12x-6x-24+24=0

We add all the numbers together, and all the variables

6x=0

x=0/6

x=0

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