24=3(21-x)+2(x-4)

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Solution for 24=3(21-x)+2(x-4) equation: 



24=3(21-x)+2(x-4)

We move all terms to the left:

24-(3(21-x)+2(x-4))=0

We add all the numbers together, and all the variables

-(3(-1x+21)+2(x-4))+24=0



We calculate terms in parentheses: -(3(-1x+21)+2(x-4)), so:

3(-1x+21)+2(x-4)

We multiply parentheses

-3x+2x+63-8

We add all the numbers together, and all the variables

-1x+55

Back to the equation:

-(-1x+55)



We get rid of parentheses

1x-55+24=0

We add all the numbers together, and all the variables

x-31=0

We move all terms containing x to the left, all other terms to the right

x=31

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