240=(4x+4)4x

Solution for 240=(4x+4)4x equation:

240=(4x+4)4x

We move all terms to the left:

240-((4x+4)4x)=0


We calculate terms in parentheses: -((4x+4)4x), so:

(4x+4)4x

We multiply parentheses

16x^2+16x

Back to the equation:

-(16x^2+16x)


We get rid of parentheses

-16x^2-16x+240=0

a = -16; b = -16; c = +240;
Δ = b2-4ac
Δ = -162-4·(-16)·240
Δ = 15616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15616}=\sqrt{256*61}=\sqrt{256}*\sqrt{61}=16\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16\sqrt{61}}{2*-16}=\frac{16-16\sqrt{61}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16\sqrt{61}}{2*-16}=\frac{16+16\sqrt{61}}{-32}
$