240=(2x+1)(6x-3)/2

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Solution for 240=(2x+1)(6x-3)/2 equation: 



240=(2x+1)(6x-3)/2

We move all terms to the left:

240-((2x+1)(6x-3)/2)=0

We multiply parentheses ..

-((+12x^2-6x+6x-3)/2)+240=0

We multiply all the terms by the denominator


-((+12x^2-6x+6x-3)+240*2)=0



We calculate terms in parentheses: -((+12x^2-6x+6x-3)+240*2), so:

(+12x^2-6x+6x-3)+240*2

We add all the numbers together, and all the variables

(+12x^2-6x+6x-3)+480

We get rid of parentheses

12x^2-6x+6x-3+480

We add all the numbers together, and all the variables

12x^2+477

Back to the equation:

-(12x^2+477)



We get rid of parentheses

-12x^2-477=0

a = -12; b = 0; c = -477;
Δ = b2-4ac
Δ = 02-4·(-12)·(-477)
Δ = -22896
Delta is less than zero, so there is no solution for the equation

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