24-(2c+4)=2(c+5+c)

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Solution for 24-(2c+4)=2(c+5+c) equation: 



24-(2c+4)=2(c+5+c)

We move all terms to the left:

24-(2c+4)-(2(c+5+c))=0

We add all the numbers together, and all the variables

-(2c+4)-(2(2c+5))+24=0

We get rid of parentheses

-2c-(2(2c+5))-4+24=0



We calculate terms in parentheses: -(2(2c+5)), so:

2(2c+5)

We multiply parentheses

4c+10

Back to the equation:

-(4c+10)



We add all the numbers together, and all the variables

-2c-(4c+10)+20=0

We get rid of parentheses

-2c-4c-10+20=0

We add all the numbers together, and all the variables

-6c+10=0

We move all terms containing c to the left, all other terms to the right

-6c=-10

c=-10/-6

c=1+2/3

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