24-(2c+4)=(c+5)+c

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Solution for 24-(2c+4)=(c+5)+c equation: 



24-(2c+4)=(c+5)+c

We move all terms to the left:

24-(2c+4)-((c+5)+c)=0

We get rid of parentheses

-2c-((c+5)+c)-4+24=0



We calculate terms in parentheses: -((c+5)+c), so:

(c+5)+c

We add all the numbers together, and all the variables

c+(c+5)

We get rid of parentheses

c+c+5

We add all the numbers together, and all the variables

2c+5

Back to the equation:

-(2c+5)



We add all the numbers together, and all the variables

-2c-(2c+5)+20=0

We get rid of parentheses

-2c-2c-5+20=0

We add all the numbers together, and all the variables

-4c+15=0

We move all terms containing c to the left, all other terms to the right

-4c=-15

c=-15/-4

c=3+3/4

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