24+3r=6(1+r)

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Solution for 24+3r=6(1+r) equation: 



24+3r=6(1+r)

We move all terms to the left:

24+3r-(6(1+r))=0

We add all the numbers together, and all the variables

3r-(6(r+1))+24=0



We calculate terms in parentheses: -(6(r+1)), so:

6(r+1)

We multiply parentheses

6r+6

Back to the equation:

-(6r+6)



We get rid of parentheses

3r-6r-6+24=0

We add all the numbers together, and all the variables

-3r+18=0

We move all terms containing r to the left, all other terms to the right

-3r=-18

r=-18/-3

r=+6

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