23x-8-19x=2(2x-5)+2

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Solution for 23x-8-19x=2(2x-5)+2 equation: 



23x-8-19x=2(2x-5)+2

We move all terms to the left:

23x-8-19x-(2(2x-5)+2)=0

We add all the numbers together, and all the variables

4x-(2(2x-5)+2)-8=0



We calculate terms in parentheses: -(2(2x-5)+2), so:

2(2x-5)+2

We multiply parentheses

4x-10+2

We add all the numbers together, and all the variables

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

4x-4x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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