23=9x2

Solution for 23=9x2 equation:

23=9x^2

We move all terms to the left:

23-(9x^2)=0

a = -9; b = 0; c = +23;
Δ = b2-4ac
Δ = 02-4·(-9)·23
Δ = 828
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{828}=\sqrt{36*23}=\sqrt{36}*\sqrt{23}=6\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{23}}{2*-9}=\frac{0-6\sqrt{23}}{-18}
=-\frac{6\sqrt{23}}{-18}
=-\frac{\sqrt{23}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{23}}{2*-9}=\frac{0+6\sqrt{23}}{-18}
=\frac{6\sqrt{23}}{-18}
=\frac{\sqrt{23}}{-3}
$