23=2x-x(x+3)

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Solution for 23=2x-x(x+3) equation: 



23=2x-x(x+3)

We move all terms to the left:

23-(2x-x(x+3))=0



We calculate terms in parentheses: -(2x-x(x+3)), so:

2x-x(x+3)

We multiply parentheses

-x^2+2x-3x

We add all the numbers together, and all the variables

-1x^2-1x

Back to the equation:

-(-1x^2-1x)



We get rid of parentheses

1x^2+1x+23=0

We add all the numbers together, and all the variables

x^2+x+23=0

a = 1; b = 1; c = +23;
Δ = b2-4ac
Δ = 12-4·1·23
Δ = -91
Delta is less than zero, so there is no solution for the equation

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