23=16+(2z-4)

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Solution for 23=16+(2z-4) equation: 



23=16+(2z-4)

We move all terms to the left:

23-(16+(2z-4))=0



We calculate terms in parentheses: -(16+(2z-4)), so:

16+(2z-4)

determiningTheFunctionDomain
(2z-4)+16

We get rid of parentheses

2z-4+16

We add all the numbers together, and all the variables

2z+12

Back to the equation:

-(2z+12)



We get rid of parentheses

-2z-12+23=0

We add all the numbers together, and all the variables

-2z+11=0

We move all terms containing z to the left, all other terms to the right

-2z=-11

z=-11/-2

z=5+1/2

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