23-b=5(b-5)

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Solution for 23-b=5(b-5) equation: 



23-b=5(b-5)

We move all terms to the left:

23-b-(5(b-5))=0

We add all the numbers together, and all the variables

-1b-(5(b-5))+23=0



We calculate terms in parentheses: -(5(b-5)), so:

5(b-5)

We multiply parentheses

5b-25

Back to the equation:

-(5b-25)



We get rid of parentheses

-1b-5b+25+23=0

We add all the numbers together, and all the variables

-6b+48=0

We move all terms containing b to the left, all other terms to the right

-6b=-48

b=-48/-6

b=+8

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