23-2x=3-2(5x-2)

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Solution for 23-2x=3-2(5x-2) equation: 



23-2x=3-2(5x-2)

We move all terms to the left:

23-2x-(3-2(5x-2))=0



We calculate terms in parentheses: -(3-2(5x-2)), so:

3-2(5x-2)

determiningTheFunctionDomain
-2(5x-2)+3

We multiply parentheses

-10x+4+3

We add all the numbers together, and all the variables

-10x+7

Back to the equation:

-(-10x+7)



We get rid of parentheses

-2x+10x-7+23=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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