23-(3s+3)s=3

Solution for 23-(3s+3)s=3 equation:

23-(3s+3)s=3

We move all terms to the left:

23-(3s+3)s-(3)=0

We add all the numbers together, and all the variables

-(3s+3)s+20=0

We multiply parentheses

-3s^2-3s+20=0

a = -3; b = -3; c = +20;
Δ = b2-4ac
Δ = -32-4·(-3)·20
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{249}}{2*-3}=\frac{3-\sqrt{249}}{-6}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{249}}{2*-3}=\frac{3+\sqrt{249}}{-6}
$