23-(2c+3)=2(c+5)+c

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Solution for 23-(2c+3)=2(c+5)+c equation: 


Simplifying
23 + -1(2c + 3) = 2(c + 5) + c

Reorder the terms:
23 + -1(3 + 2c) = 2(c + 5) + c
23 + (3 * -1 + 2c * -1) = 2(c + 5) + c
23 + (-3 + -2c) = 2(c + 5) + c

Combine like terms: 23 + -3 = 20
20 + -2c = 2(c + 5) + c

Reorder the terms:
20 + -2c = 2(5 + c) + c
20 + -2c = (5 * 2 + c * 2) + c
20 + -2c = (10 + 2c) + c

Combine like terms: 2c + c = 3c
20 + -2c = 10 + 3c

Solving
20 + -2c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
20 + -2c + -3c = 10 + 3c + -3c

Combine like terms: -2c + -3c = -5c
20 + -5c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
20 + -5c = 10 + 0
20 + -5c = 10

Add '-20' to each side of the equation.
20 + -20 + -5c = 10 + -20

Combine like terms: 20 + -20 = 0
0 + -5c = 10 + -20
-5c = 10 + -20

Combine like terms: 10 + -20 = -10
-5c = -10

Divide each side by '-5'.
c = 2

Simplifying
c = 2

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