23+4y-3=12y-10-2y

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Solution for 23+4y-3=12y-10-2y equation: 



23+4y-3=12y-10-2y

We move all terms to the left:

23+4y-3-(12y-10-2y)=0

We add all the numbers together, and all the variables

4y-(10y-10)+23-3=0

We add all the numbers together, and all the variables

4y-(10y-10)+20=0

We get rid of parentheses

4y-10y+10+20=0

We add all the numbers together, and all the variables

-6y+30=0

We move all terms containing y to the left, all other terms to the right

-6y=-30

y=-30/-6

y=+5

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