23(y+40)=10(3y-13)

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Solution for 23(y+40)=10(3y-13) equation: 



23(y+40)=10(3y-13)

We move all terms to the left:

23(y+40)-(10(3y-13))=0

We multiply parentheses

23y-(10(3y-13))+920=0



We calculate terms in parentheses: -(10(3y-13)), so:

10(3y-13)

We multiply parentheses

30y-130

Back to the equation:

-(30y-130)



We get rid of parentheses

23y-30y+130+920=0

We add all the numbers together, and all the variables

-7y+1050=0

We move all terms containing y to the left, all other terms to the right

-7y=-1050

y=-1050/-7

y=+150

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