23(x-1)-8=4(1+x)+5

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Solution for 23(x-1)-8=4(1+x)+5 equation: 



23(x-1)-8=4(1+x)+5

We move all terms to the left:

23(x-1)-8-(4(1+x)+5)=0

We add all the numbers together, and all the variables

23(x-1)-(4(x+1)+5)-8=0

We multiply parentheses

23x-(4(x+1)+5)-23-8=0



We calculate terms in parentheses: -(4(x+1)+5), so:

4(x+1)+5

We multiply parentheses

4x+4+5

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

23x-(4x+9)-31=0

We get rid of parentheses

23x-4x-9-31=0

We add all the numbers together, and all the variables

19x-40=0

We move all terms containing x to the left, all other terms to the right

19x=40

x=40/19

x=2+2/19

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