23(3x+3)-5x=40

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Solution for 23(3x+3)-5x=40 equation:



23(3x+3)-5x=40
We move all terms to the left:
23(3x+3)-5x-(40)=0
We add all the numbers together, and all the variables
-5x+23(3x+3)-40=0
We multiply parentheses
-5x+69x+69-40=0
We add all the numbers together, and all the variables
64x+29=0
We move all terms containing x to the left, all other terms to the right
64x=-29
x=-29/64
x=-29/64

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