23(35x+9)=14(2x+40)x=

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Solution for 23(35x+9)=14(2x+40)x= equation: 



23(35x+9)=14(2x+40)x=

We move all terms to the left:

23(35x+9)-(14(2x+40)x)=0

We multiply parentheses

805x-(14(2x+40)x)+207=0



We calculate terms in parentheses: -(14(2x+40)x), so:

14(2x+40)x

We multiply parentheses

28x^2+560x

Back to the equation:

-(28x^2+560x)



We get rid of parentheses

-28x^2+805x-560x+207=0

We add all the numbers together, and all the variables

-28x^2+245x+207=0

a = -28; b = 245; c = +207;
Δ = b2-4ac
Δ = 2452-4·(-28)·207
Δ = 83209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(245)-\sqrt{83209}}{2*-28}=\frac{-245-\sqrt{83209}}{-56}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(245)+\sqrt{83209}}{2*-28}=\frac{-245+\sqrt{83209}}{-56}
$

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