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22x+5+32x-5=5x+54x^2-25
We move all terms to the left:
22x+5+32x-5-(5x+54x^2-25)=0
We add all the numbers together, and all the variables
-(5x+54x^2-25)+54x=0
We get rid of parentheses
-54x^2-5x+54x+25=0
We add all the numbers together, and all the variables
-54x^2+49x+25=0
a = -54; b = 49; c = +25;
Δ = b2-4ac
Δ = 492-4·(-54)·25
Δ = 7801
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{7801}}{2*-54}=\frac{-49-\sqrt{7801}}{-108} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{7801}}{2*-54}=\frac{-49+\sqrt{7801}}{-108} $
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