22x+2=10x+47

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Solution for 22x+2=10x+47 equation: 



22x+2=10x+47

We move all terms to the left:

22x+2-(10x+47)=0

We get rid of parentheses

22x-10x-47+2=0

We add all the numbers together, and all the variables

12x-45=0

We move all terms containing x to the left, all other terms to the right

12x=45

x=45/12

x=3+3/4

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