22b+15=2(3b+3)+17b+5

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Solution for 22b+15=2(3b+3)+17b+5 equation: 



22b+15=2(3b+3)+17b+5

We move all terms to the left:

22b+15-(2(3b+3)+17b+5)=0



We calculate terms in parentheses: -(2(3b+3)+17b+5), so:

2(3b+3)+17b+5

We add all the numbers together, and all the variables

17b+2(3b+3)+5

We multiply parentheses

17b+6b+6+5

We add all the numbers together, and all the variables

23b+11

Back to the equation:

-(23b+11)



We get rid of parentheses

22b-23b-11+15=0

We add all the numbers together, and all the variables

-1b+4=0

We move all terms containing b to the left, all other terms to the right

-b=-4

b=-4/-1

b=+4

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