22=7(x-4)-22

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Solution for 22=7(x-4)-22 equation: 



22=7(x-4)-22

We move all terms to the left:

22-(7(x-4)-22)=0



We calculate terms in parentheses: -(7(x-4)-22), so:

7(x-4)-22

We multiply parentheses

7x-28-22

We add all the numbers together, and all the variables

7x-50

Back to the equation:

-(7x-50)



We get rid of parentheses

-7x+50+22=0

We add all the numbers together, and all the variables

-7x+72=0

We move all terms containing x to the left, all other terms to the right

-7x=-72

x=-72/-7

x=10+2/7

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