22=6+(2/3)x

Solution for 22=6+(2/3)x equation:

22=6+(2/3)x

We move all terms to the left:

22-(6+(2/3)x)=0


Domain of the equation: 3)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-(6+(+2/3)x)+22=0

We multiply all the terms by the denominator


-(6+(+2+22*3)x)=0


We calculate terms in parentheses: -(6+(+2+22*3)x), so:

6+(+2+22*3)x

determiningTheFunctionDomain
(+2+22*3)x+6

We add all the numbers together, and all the variables

68x+6

Back to the equation:

-(68x+6)


We get rid of parentheses

-68x-6=0

We move all terms containing x to the left, all other terms to the right

-68x=6

x=6/-68

x=-3/34