22=-2(4v+1)+2v

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Solution for 22=-2(4v+1)+2v equation: 



22=-2(4v+1)+2v

We move all terms to the left:

22-(-2(4v+1)+2v)=0



We calculate terms in parentheses: -(-2(4v+1)+2v), so:

-2(4v+1)+2v

We add all the numbers together, and all the variables

2v-2(4v+1)

We multiply parentheses

2v-8v-2

We add all the numbers together, and all the variables

-6v-2

Back to the equation:

-(-6v-2)



We get rid of parentheses

6v+2+22=0

We add all the numbers together, and all the variables

6v+24=0

We move all terms containing v to the left, all other terms to the right

6v=-24

v=-24/6

v=-4

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