22=(x+3)+(4x+1)/2

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Solution for 22=(x+3)+(4x+1)/2 equation: 



22=(x+3)+(4x+1)/2

We move all terms to the left:

22-((x+3)+(4x+1)/2)=0

We multiply all the terms by the denominator


-((x+3)+(4x+1)+22*2)=0



We calculate terms in parentheses: -((x+3)+(4x+1)+22*2), so:

(x+3)+(4x+1)+22*2

We add all the numbers together, and all the variables

(x+3)+(4x+1)+44

We get rid of parentheses

x+4x+3+1+44

We add all the numbers together, and all the variables

5x+48

Back to the equation:

-(5x+48)



We get rid of parentheses

-5x-48=0

We move all terms containing x to the left, all other terms to the right

-5x=48

x=48/-5

x=-9+3/5

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