2250=(20-2x)(30+3x)

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Solution for 2250=(20-2x)(30+3x) equation: 



2250=(20-2x)(30+3x)

We move all terms to the left:

2250-((20-2x)(30+3x))=0

We add all the numbers together, and all the variables

-((-2x+20)(3x+30))+2250=0

We multiply parentheses ..

-((-6x^2-60x+60x+600))+2250=0



We calculate terms in parentheses: -((-6x^2-60x+60x+600)), so:

(-6x^2-60x+60x+600)

We get rid of parentheses

-6x^2-60x+60x+600

We add all the numbers together, and all the variables

-6x^2+600

Back to the equation:

-(-6x^2+600)



We get rid of parentheses

6x^2-600+2250=0

We add all the numbers together, and all the variables

6x^2+1650=0

a = 6; b = 0; c = +1650;
Δ = b2-4ac
Δ = 02-4·6·1650
Δ = -39600
Delta is less than zero, so there is no solution for the equation

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