224=240t-16t2

Solution for 224=240t-16t2 equation:

224=240t-16t^2

We move all terms to the left:

224-(240t-16t^2)=0

We get rid of parentheses

16t^2-240t+224=0

a = 16; b = -240; c = +224;
Δ = b2-4ac
Δ = -2402-4·16·224
Δ = 43264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{43264}=208$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-208}{2*16}=\frac{32}{32}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+208}{2*16}=\frac{448}{32}
=14
$