222=2(5y+4y+3)

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Solution for 222=2(5y+4y+3) equation: 



222=2(5y+4y+3)

We move all terms to the left:

222-(2(5y+4y+3))=0

We add all the numbers together, and all the variables

-(2(9y+3))+222=0



We calculate terms in parentheses: -(2(9y+3)), so:

2(9y+3)

We multiply parentheses

18y+6

Back to the equation:

-(18y+6)



We get rid of parentheses

-18y-6+222=0

We add all the numbers together, and all the variables

-18y+216=0

We move all terms containing y to the left, all other terms to the right

-18y=-216

y=-216/-18

y=+12

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