220d2-88d=22(10d-4)

Solution for 220d2-88d=22(10d-4) equation:

220d^2-88d=22(10d-4)

We move all terms to the left:

220d^2-88d-(22(10d-4))=0


We calculate terms in parentheses: -(22(10d-4)), so:

22(10d-4)

We multiply parentheses

220d-88

Back to the equation:

-(220d-88)


We get rid of parentheses

220d^2-88d-220d+88=0

We add all the numbers together, and all the variables

220d^2-308d+88=0

a = 220; b = -308; c = +88;
Δ = b2-4ac
Δ = -3082-4·220·88
Δ = 17424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{17424}=132$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-308)-132}{2*220}=\frac{176}{440}
=2/5
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-308)+132}{2*220}=\frac{440}{440}
=1
$