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22-x=5(2+x)
We move all terms to the left:
22-x-(5(2+x))=0
We add all the numbers together, and all the variables
-x-(5(x+2))+22=0
We add all the numbers together, and all the variables
-1x-(5(x+2))+22=0
We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
-1x-5x-10+22=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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