22-v=-4+2(4+v)

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Solution for 22-v=-4+2(4+v) equation: 



22-v=-4+2(4+v)

We move all terms to the left:

22-v-(-4+2(4+v))=0

We add all the numbers together, and all the variables

-v-(-4+2(v+4))+22=0

We add all the numbers together, and all the variables

-1v-(-4+2(v+4))+22=0



We calculate terms in parentheses: -(-4+2(v+4)), so:

-4+2(v+4)

determiningTheFunctionDomain
2(v+4)-4

We multiply parentheses

2v+8-4

We add all the numbers together, and all the variables

2v+4

Back to the equation:

-(2v+4)



We get rid of parentheses

-1v-2v-4+22=0

We add all the numbers together, and all the variables

-3v+18=0

We move all terms containing v to the left, all other terms to the right

-3v=-18

v=-18/-3

v=+6

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