22-7(2x-2)=x-4(5+x)

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Solution for 22-7(2x-2)=x-4(5+x) equation: 



22-7(2x-2)=x-4(5+x)

We move all terms to the left:

22-7(2x-2)-(x-4(5+x))=0

We add all the numbers together, and all the variables

-7(2x-2)-(x-4(x+5))+22=0

We multiply parentheses

-14x-(x-4(x+5))+14+22=0



We calculate terms in parentheses: -(x-4(x+5)), so:

x-4(x+5)

We multiply parentheses

x-4x-20

We add all the numbers together, and all the variables

-3x-20

Back to the equation:

-(-3x-20)



We add all the numbers together, and all the variables

-14x-(-3x-20)+36=0

We get rid of parentheses

-14x+3x+20+36=0

We add all the numbers together, and all the variables

-11x+56=0

We move all terms containing x to the left, all other terms to the right

-11x=-56

x=-56/-11

x=5+1/11

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