22-4n=-6(n-2)

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Solution for 22-4n=-6(n-2) equation: 



22-4n=-6(n-2)

We move all terms to the left:

22-4n-(-6(n-2))=0



We calculate terms in parentheses: -(-6(n-2)), so:

-6(n-2)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)



We get rid of parentheses

-4n+6n-12+22=0

We add all the numbers together, and all the variables

2n+10=0

We move all terms containing n to the left, all other terms to the right

2n=-10

n=-10/2

n=-5

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