22-(2x/3+x)=2

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Solution for 22-(2x/3+x)=2 equation: 



22-(2x/3+x)=2

We move all terms to the left:

22-(2x/3+x)-(2)=0



Domain of the equation: 3+x)!=0

We move all terms containing x to the left, all other terms to the right

x)!=-3

x!=-3/1

x!=-3

x∈R



We add all the numbers together, and all the variables

-(+x+2x/3)+22-2=0

We add all the numbers together, and all the variables

-(+x+2x/3)+20=0

We get rid of parentheses

-x-2x/3+20=0

We multiply all the terms by the denominator


-x*3-2x+20*3=0

We add all the numbers together, and all the variables

-2x-x*3+60=0

Wy multiply elements

-2x-3x+60=0

We add all the numbers together, and all the variables

-5x+60=0

We move all terms containing x to the left, all other terms to the right

-5x=-60

x=-60/-5

x=+12

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