22+4r=-2(1+6r)+4r

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Solution for 22+4r=-2(1+6r)+4r equation:



22+4r=-2(1+6r)+4r
We move all terms to the left:
22+4r-(-2(1+6r)+4r)=0
We add all the numbers together, and all the variables
4r-(-2(6r+1)+4r)+22=0
We calculate terms in parentheses: -(-2(6r+1)+4r), so:
-2(6r+1)+4r
We add all the numbers together, and all the variables
4r-2(6r+1)
We multiply parentheses
4r-12r-2
We add all the numbers together, and all the variables
-8r-2
Back to the equation:
-(-8r-2)
We get rid of parentheses
4r+8r+2+22=0
We add all the numbers together, and all the variables
12r+24=0
We move all terms containing r to the left, all other terms to the right
12r=-24
r=-24/12
r=-2

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