22(x-2)+5=4(x-6)+33

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Solution for 22(x-2)+5=4(x-6)+33 equation: 



22(x-2)+5=4(x-6)+33

We move all terms to the left:

22(x-2)+5-(4(x-6)+33)=0

We multiply parentheses

22x-(4(x-6)+33)-44+5=0



We calculate terms in parentheses: -(4(x-6)+33), so:

4(x-6)+33

We multiply parentheses

4x-24+33

We add all the numbers together, and all the variables

4x+9

Back to the equation:

-(4x+9)



We add all the numbers together, and all the variables

22x-(4x+9)-39=0

We get rid of parentheses

22x-4x-9-39=0

We add all the numbers together, and all the variables

18x-48=0

We move all terms containing x to the left, all other terms to the right

18x=48

x=48/18

x=2+2/3

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