22(v-6)=10

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Solution for 22(v-6)=10 equation: 



22(v-6)=10

We move all terms to the left:

22(v-6)-(10)=0

We multiply parentheses

22v-132-10=0

We add all the numbers together, and all the variables

22v-142=0

We move all terms containing v to the left, all other terms to the right

22v=142

v=142/22

v=6+5/11

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