22(2x+5)=16(x+10)

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Solution for 22(2x+5)=16(x+10) equation: 



22(2x+5)=16(x+10)

We move all terms to the left:

22(2x+5)-(16(x+10))=0

We multiply parentheses

44x-(16(x+10))+110=0



We calculate terms in parentheses: -(16(x+10)), so:

16(x+10)

We multiply parentheses

16x+160

Back to the equation:

-(16x+160)



We get rid of parentheses

44x-16x-160+110=0

We add all the numbers together, and all the variables

28x-50=0

We move all terms containing x to the left, all other terms to the right

28x=50

x=50/28

x=1+11/14

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