21y-(7y-2)=16y-2(4y-13)

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Solution for 21y-(7y-2)=16y-2(4y-13) equation: 



21y-(7y-2)=16y-2(4y-13)

We move all terms to the left:

21y-(7y-2)-(16y-2(4y-13))=0

We get rid of parentheses

21y-7y-(16y-2(4y-13))+2=0



We calculate terms in parentheses: -(16y-2(4y-13)), so:

16y-2(4y-13)

We multiply parentheses

16y-8y+26

We add all the numbers together, and all the variables

8y+26

Back to the equation:

-(8y+26)



We add all the numbers together, and all the variables

14y-(8y+26)+2=0

We get rid of parentheses

14y-8y-26+2=0

We add all the numbers together, and all the variables

6y-24=0

We move all terms containing y to the left, all other terms to the right

6y=24

y=24/6

y=4

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