21y^2-32y+12=0

Solution for 21y^2-32y+12=0 equation:

Simplifying
21y2 + -32y + 12 = 0

Reorder the terms:
12 + -32y + 21y2 = 0

Solving
12 + -32y + 21y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(2 + -3y)(6 + -7y) = 0

Subproblem 1
Set the factor '(2 + -3y)' equal to zero and attempt to solve:

Simplifying
2 + -3y = 0

Solving
2 + -3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -3y = 0 + -2
-3y = 0 + -2

Combine like terms: 0 + -2 = -2
-3y = -2

Divide each side by '-3'.
y = 0.6666666667

Simplifying
y = 0.6666666667
Subproblem 2
Set the factor '(6 + -7y)' equal to zero and attempt to solve:

Simplifying
6 + -7y = 0

Solving
6 + -7y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + -7y = 0 + -6

Combine like terms: 6 + -6 = 0
0 + -7y = 0 + -6
-7y = 0 + -6

Combine like terms: 0 + -6 = -6
-7y = -6

Divide each side by '-7'.
y = 0.8571428571

Simplifying
y = 0.8571428571
Solution
y = {0.6666666667, 0.8571428571}