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21x^2+81x+14=0
a = 21; b = 81; c = +14;
Δ = b2-4ac
Δ = 812-4·21·14
Δ = 5385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-\sqrt{5385}}{2*21}=\frac{-81-\sqrt{5385}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+\sqrt{5385}}{2*21}=\frac{-81+\sqrt{5385}}{42} $
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