21x+1=6(x+2)

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Solution for 21x+1=6(x+2) equation: 



21x+1=6(x+2)

We move all terms to the left:

21x+1-(6(x+2))=0



We calculate terms in parentheses: -(6(x+2)), so:

6(x+2)

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

21x-6x-12+1=0

We add all the numbers together, and all the variables

15x-11=0

We move all terms containing x to the left, all other terms to the right

15x=11

x=11/15

x=11/15

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