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21w^2-4w-1=0
a = 21; b = -4; c = -1;
Δ = b2-4ac
Δ = -42-4·21·(-1)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-10}{2*21}=\frac{-6}{42} =-1/7 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+10}{2*21}=\frac{14}{42} =1/3 $
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