21p-4=(12p+7/2)

Solution for 21p-4=(12p+7/2) equation:

21p-4=(12p+7/2)

We move all terms to the left:

21p-4-((12p+7/2))=0

We add all the numbers together, and all the variables

21p-((+12p+7/2))-4=0

We multiply all the terms by the denominator


21p*2))-((+12p+7-4*2))=0

We add all the numbers together, and all the variables

21p*2))-((12p-1))=0

We add all the numbers together, and all the variables

21p*2))-((12p=0

Wy multiply elements

42p^2=0

a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{84}=0$