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21=x+1/5x
We move all terms to the left:
21-(x+1/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x+1/5x)+21=0
We get rid of parentheses
-x-1/5x+21=0
We multiply all the terms by the denominator
-x*5x+21*5x-1=0
Wy multiply elements
-5x^2+105x-1=0
a = -5; b = 105; c = -1;
Δ = b2-4ac
Δ = 1052-4·(-5)·(-1)
Δ = 11005
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-\sqrt{11005}}{2*-5}=\frac{-105-\sqrt{11005}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+\sqrt{11005}}{2*-5}=\frac{-105+\sqrt{11005}}{-10} $
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