21=7(r-5)/3

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Solution for 21=7(r-5)/3 equation: 



21=7(r-5)/3

We move all terms to the left:

21-(7(r-5)/3)=0

We multiply all the terms by the denominator


-(7(r-5)+21*3)=0



We calculate terms in parentheses: -(7(r-5)+21*3), so:

7(r-5)+21*3

We add all the numbers together, and all the variables

7(r-5)+63

We multiply parentheses

7r-35+63

We add all the numbers together, and all the variables

7r+28

Back to the equation:

-(7r+28)



We get rid of parentheses

-7r-28=0

We move all terms containing r to the left, all other terms to the right

-7r=28

r=28/-7

r=-4

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